Solve The Following Pair Of Equations By Reducing Them To A Pair Of Linear Equations 2 X 3 Y 2 4 X 9 Y 1
Subtract 2 from both sides \frac {2} {5}x=y2 5 2 x = y − 2 Divide both sides of the equation by \frac {2} {5}, which is the same as multiplying both sides by the reciprocal of the fraction Divide both sides of the equation by 5 2 , which is the same as comment 4 report flag outlined umm report flag outlined wait mine is wrong i put 1/2 not 1/5 report flag outlined are you sure im taking a huge test and want this to be sure before i dont dought you but r u sure report flag outlined
33.solve quad (5)/(x-1)+(1)/(y-2)=2 (6)/(x-1)-(3)/(y-2)=1
33.solve quad (5)/(x-1)+(1)/(y-2)=2 (6)/(x-1)-(3)/(y-2)=1-Step 1 The answer is in slopeintercept form where m is the slope and b is the yintercept when x=0 at point (0,b) In this example, the answer reveals that m=5/2 and b=5 Step 2 To get this equation from , use the following steps Multiply by 10 to both sides of the equation to get rid of the denominators Subtract 5x from both sides of the equation Divide 2 to both sides of the equationExercise 155 Solve y' (x y 1)2 ;
This Figure Shows The Dynamics Of The Solution Of The System X N 1 Y Download Scientific Diagram
Subtract 5 from both sides x=\frac {0±\sqrt {0^ {2}4\left (y^ {2}5\right)}} {2} This equation is in standard form ax^ {2}bxc=0 Substitute 1 for a, 0 for b, and y^ {2}5 for c in the quadratic formula, \frac {b±\sqrt {b^ {2}4ac}} {2a} x=\frac {0±\sqrt {4\left (y^ {2}5\right)}} {2} Square 0See the answer See the answer See the answer done loading Show transcribed image text Expert Answer Who are the experts?Graph y=1/2x5 Rewrite in slopeintercept form Tap for more steps The slopeintercept form is , where is the slope and is the yintercept To find the xintercept (s), substitute in for and solve for Solve the equation Tap for more steps Rewrite the equation as
Start with the given system of equations In order to graph these equations, weSolve x/5 =2 1/2; raun2625 Ambitious 5 answers 1K people helped 5/x11/y2=2 eq 1 6/x13/y2=1 eq 2 let 1/x1=u, 1/y2=v multiply eq 1 by 3, we get 15u=3v=6 eq 3
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